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200 m500 m900 m400 m
Answer : A
Solution : Here, acceleration, `a = 4 ms^(-2)`, time taken, `t = 10 s` <br> initial velocity, `u = 0`, distance, `s = ?` <br> From `s = ut + (1)/(2)at^(2)`, `s = 0 xx 10 + (1)/(2) xx 4 (10)^(2) = 200 m`
Text Solution
Solution : Initial Velocity of the car, u = 0`ms^(-1)` <br> Acceleration, a = 4m `s^(-2)` <br> Time, t = 10 s <br> We know Distance, s = ut + (1/2) `at^(2)` <br> Therefore, Distance covered by car in 10 second = `0xx10+(1//2)xx4xx102` <br> = `0+(1//2)xx4xx10xx10m ` <br> = `(1//2) xx400m ` <br> = 200m
A racing car has a uniform acceleration of 4 ms 2. What distance will it cover in 10 s after start?
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