B.
8.360 × 104 K
Let at temperature T rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere
Vescape = 11200 m/s
Also, Vrms = Vescape = 3kBTmO2 = 11200 m/s
Putting value of KB and mO2 we get,
T = 8.360 x 104 K
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Answer
Text Solution
Solution : As is known, translational kinetic energy of a molecule `= 3/2 kT` <br> The oxygen molecule will escape from earth, <br> when `3/2 kT ge 1/2 m upsilon_(e)^(2)` <br> `T ge (m upsilon_(e)^(2))/(3k)` <br> `T ge (2.76 xx 10^(-26) (11.2 xx 10^(3))^(2))/(3 xx 1.38 xx 10^(-23))` <br> `T ge 8.36 xx 10^(4) K`.
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