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Text Solution
Solution : since `n_(1) = 5 and n_(1) = 2 `, this transition gives rise to a spectral line in the visible region of the balmer series. From equation <br> `DeltaE=2.18xx10^(-18)J[1/5^(2)-1/2^(2)]` <br>` 4.58xx 10^(-19)J` <br> it is an emission energy <br> the frequency of the photon ( taking energy in terms of magnitude ) is given by <br> `v=(DeltaE)/h` <br> `( 4.58xx10^(-19)J)/(6.626xx10^(-34) Js)` <br> `6.91xx10^(14)Hz` <br> ` lambda=c/v= (3.0xx10^(8)m s^(-1))/(6.91xx10^(14)Hz)=434 nm`
What are the frequency and wavelength of a photon emitted during a transition from n=5 state to the n=2 state in the hydrogen atom ?
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