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Answer
5
Text Solution
3 mol 4 mol 1 mol 2 mol
Answer : D
Solution : <img src="//doubtnut-static.s.llnwi.net/static/physics_images/MTG_NEET_GID_CHE_XI_C01_E01_165_S01.png" width="80%"> <br> 10 g of `H_2` = 5 mol and 32 g of `O_2` = 1 mol <br> ` therefore ` In this reaction, oxygen is the limiting reagent so amount of `H_2 O` produced depends on amount of `O_2`. <br> Since 0.5 mol of `O_2` gives 1 mol `H_2 O` <br> ` therefore ` 1 mol of `O_2` will give 2 mol `H_2 O`.