Let AB be the tower and BC be the length of the shadow of the tower.
Here, θ is the angle of elevation of the sun.
Given, length of shadow of tower = `sqrt3` × Height of the tower
BC = `sqrt3` AB ... (1)
In right ΔABC
`tanO/=(AB)/(BC)` `(tanO/=(\text{opposite side})/\text{opposite side})`
`thereforetanO/=(AB)/sqrt(AB)` `\text{Using} (1)`
`rArrtanO/=1/sqrt3`
`rArrtan=tan 30^@` `(thereforetan30^@=1/sqrt3)`
`rArrO/=30^@`
Thus, the angle of elevation of the sun is 30°.
Hence, the correct answer is B.
If the length of the shadow of a tower is √3 times its height then the angle of elevation of the sun is a 45∘ b 30∘ c 60∘ d 90∘
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tan∠ACB =h√3×h
tan∠ACB = 1√3
∠ACB=30∘
Therefore, angle of elevation is 30∘
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