Text Solution
Answer : `19.47^(@)`
Solution : Here, `.^(a)n_(g) = 1.5, i= 30^(@), r = ?`<br> From `.^(a)n_(g) = (sini)/(sinr)`, <br> ` sin r = (sin i)/(.^(a)n_(g)) = (sin30^(@))/(1.5) = (1//2)/(1.5) = 0.3333` <br> or `r = 19.47^(@)` (using tables of nature sines)
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