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Correct Answer:
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Let principal amount be Rs.100. Then, S.I. = \( \Large \frac{100 \times 20 \times 3}{100} \) = Rs.60and C.I. = 100 \( \Large ( 1 + \frac{20}{100} ) ^ {3} - 100 \)= \( \Large 100 \times (\frac{6}{5})^{3} - 100 = \frac{364}{5} \)\( \Large \therefore \) C.I. - S.I. = \( \Large \frac{364}{5} - 60 = \frac{64}{5} \)If difference is Rs.\( \Large \frac{64}{5} \), Principal = Rs.100If difference is Rs.48
Principal = \( \Large \frac{100 \times 5}{64} \times 48 \) = Rs.375
Part of solved Simple and compound interest questions and answers : >> Aptitude >> Simple and compound interest
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Given:
CI – SI = 100
T = 2 years
R = 5 %
Formula:
SI = PRT/100
CI = P(1 + R/100)n - P
Here SI = Simple interest, P = Principal, R = Rate, T = Time, CI = Compound interest
Calculations:
Let the Sum be Rs. x.
Compound interest = x[1 + 5/100]2 – x
⇒ (441/400)x – x
⇒ (41/400)x
Simple Interest = (x × 5 × 2)/100 = 10x/100
⇒ 41x/400 – 10x/100 = 100
⇒ x/400 = 100
⇒ x = 40,000
∴ The Sum is Rs. 40,000.
Let the Sum be Rs. x.
By using Formula;
Difference = Principal(Rate/100)Time
⇒ 100 = x(5/100)2
⇒ x = 40,000
∴ The Sum is Rs. 40,000.
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If the difference between the simple interest and compound interest on some principal amount at 20
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