Text Solution
`2r, 2pi r ``r l2, pi r ``2r, pi r ``r, pir `
Answer : C
Solution : Distance travelled by particle in circular path = length of semicircular path `= 1/2 xx` circumferene `= 1/2 xx 2 pi r= pi r ` and magnitude of displacement = distance between the opposite point on smicircular path = 2 r.
Distance and displacement are both same and equal to 0
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Distance and displacement are both same and equal to 2πr
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Distance = 0 and displacement = 2πr
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Distance = 2πr and displacement = 0
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