What is the largest two digit number which when divided by 3/4 and 6 leaves the remainder 1 2 and 4 respectively what is the remainder when n is divided by 5?

Solution

Given remainders are 1,2 and 4 for 3,4 and 6 respectively so in each case negative remainder is 1-3,2-4,4-6i.e -2,-2 and -2So in each case it has same negative remainder so the number should be in the form of LCM(3,4,6)-2i.e 12k-6As given largest 2 digit number we have for k=8 ,12*8-2=96-2=94

When 94 is divided by 5 remainder is 4