CBSE 11-science - Chemistry 696v7v
Asked by aryanvankar88 | 11 Oct, 2020, 10:07: PM ANSWERED BY EXPERT
CBSE 11-science - Chemistry 5.18 sum plz
Asked by lovemaan5500 | 26 Jan, 2019, 12:53: PM ANSWERED BY EXPERT Text Solution Answer : The required temperature is `546^@C`. Solution : Let the volume at `0^@C` = V ml. <br> `V_1 = VmL, V_2 = 3 mL` <br>`T_1 = 0^@` or `273 K, T_2 = ?` <br> by charles law, <br> ` V_1/T_1 = V_2/T_2` or `V/273 =(3V)/T_2` <br> or `T_2 = (3xx273) = 819 K` <br> or `T_2 = (819-273)^@C = 546^@C` No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! |