For what value of K does the pair of equations given below has a unique solution$$y-x=6$$ and $$3kx+2y=7$$ For unique solution,
$$\dfrac{a_{1}}{a_{2}}\neq \dfrac{b_{1}}{b_{2}}$$
Therefore,
$$\dfrac{1}{3k}\neq \dfrac{-1}{2}$$
$$k\neq \dfrac{-2}{3}$$