how long would it take for a ball dropped from the top of a 144 foot building to hit the ground As an object falls, its speed increases because it’s being pulled on by gravity. The acceleration of gravity near the earth is g = 32.2 feet/sec^2. The formula for T = time of the fall is T = (2d/g)^0.5 where d = 1440 foot and g = 32.2 feet/sec^2 T = (2*1440/32.2)^0.5 T = 9.457 sec approximately. The ball will hit the ground in approximately 9.457 seconds.
Kim O. 1 Expert Answer To solve this problem you need the function v0 is the initial velocity, which in our case is 0 h0 = initial height, which in our case is 256 h(t) = 0 since we want to know when the ball will hit the ground. If we rearrange the terms we see that this is a difference of 2 squares The second solution is discarded as time cannot be negative. So the ball will hit the ground in 4 seconds.
You can put this solution on YOUR website! 16t^2 = 196 t^2 = 196/16 t^2 = 12.25 t = sqrt(12.25) t = 3.5 So roughly 3.5 seconds |