What is the normality of a 2.0 M H2SO4 solution?

Q: What is the normality of a 1.0 M H2SO4 solution?

Thus, a 1 M solution of H2SO4 will be 2 N. The normality of a solution is the molarity multiplied by the number of equivalents per mole.

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What is normality of 2M H2SO4 solution?
What is the normality of a 1.0 M H2SO4 solution?
How do you make a 2M H2SO4 solution?
How do you calculate normality of H2SO4?

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Hint: Normality is denoted by letter N and is referred to as the equivalent concentration of a solution. Normally it is calculated according to the formula:
$N = Molarity \times Basicity$
Or $N = Molarity \times Acidity$

Complete step by step answer:
Normality is one of the expressions used to measure the concentration of a solution.
Normality as per definition is defined as the number of gram or mole equivalents of solute present in one litre of the solution.
Normality can be calculated using number of formulas:
$Normality = \dfrac{{\left( {Number{\text{ of gram equivalents}}} \right)}}{{Volume{\text{ of solution in litres}}}}$

$Normality = Weight{\text{ of solute (gram)}} \times {\text{Equivalent weight}} \times {\text{Volume (L)}}$

$N = Molarity \times Molar{\text{ mass}} \times {\left[ {equivalent{\text{ mass}}} \right]^{ - 1}}$

$N = Molarity \times {\text{Basicity}}$
Or
$N = Molarity \times Acidity$
The units of normality are$eq{L^{ - 1}}$or $meq{L^{ - 1}}$.
Now, in the given question we have to calculate the normality of 2M ${H_2}S{O_4}$.
As we know that, the acidity is the number of replaceable ${H^ + }$ ions present in an acid.
So, for ${H_2}S{O_4}$, there are two replaceable ${H^ + }$ ions in ${H_2}S{O_4}$.
Therefore, acidity= 2
Now, using the formula,
$Normality = Molarity \times Acidity$
N=$2 \times 2$ [Molarity is given to be 2M]
N= 4N
Hence, the normality of 2M ${H_2}S{O_4}$ is 4 N.

Note:
The term number of gram equivalents is related to normality. Gram equivalents refer to the ratio of weight of the solute to the equivalent weight of the solute.

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Normality of 2M sulphuric acid...

Updated On: 27-06-2022

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Text Solution

`2N``4N``N//2``N//4`

Answer : B

Solution : `N=Mxx "basicity" , N=2xx2=4N`

Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

12654392

300

7.3 K

1:41

Normality of `2`M sulphuric acid is

201232086

3.5 K

1:25

Normality of 1.25 M sulphuric acid is

647807696

6.8 K

Normality of 1.25 M sulphuric acid is:

648521733

1.8 K

Normality of `1.25`M sulphuric acid is

643010446

500

2:14

Normality of pure sulphuric acid is:

403356136

9.7 K

1:25

Normality of 1.25 M sulphuric acid is

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What is normality of 2M H2SO4 solution?

Normality =n× Molarity=2×2=4 N.

What is the normality of a 1.0 M H2SO4 solution?

Thus, a 1 M solution of H₂SO₄ will be 2 N. The normality of a solution is the molarity multiplied by the number of equivalents per mole.

How do you make a 2M H2SO4 solution?

So you take 900 ml of plain water, add your 100ml of concentrated H2SO4. Mix all this together and you now have 2 moles of H2SO4 in 1L of solution…. that is 2M H2SO4.

How do you calculate normality of H2SO4?

Normality is defined as the gram equivalence of solute per litre of solution. Gram equivalence is calculated based on the number of ions that react in a chemical reaction. In 1 mol H 2 SO 4 , 2 H + ion reacts in the given reaction. N = g r a m e q u i v a l e n c e o f s o l u t e V o l u m e o f s o l u t i o n .