What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24?

Question 8 Exercise 3.7

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Answer:

SOLUTION:

To find the smallest digit divisble by 6,8 and 12

we need to find the LCM of 6,8 and 12

6,8,12=2\times2\times2\times3=24

100+24-4=120

120 is the smallest digit divisible by 6,8 and 12.

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