What is the Coulombs force between two alpha particles separated by a distance?

CBSE 12-science - Physics

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Asked by carnivalgirl8421 | 29 Jun, 2022, 10:06: PM

Four point charges qA = 2 μC, qB = – 5 μC, qc = 2 μC, and qD = –5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?

Suppose a square ABCD with each side of 10 cm and centre 0. At the centre, the charge of 1 μC is placed.

The force between two alpha particles separated by a distance r is f.in order to have same force f the distance between singly ionized chlorine atoms separated by a distance of 1. 2 r2.4 r3 . r / 24 . r / 4

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Text Solution

`90 N``45 N``60 N``75 N`

Answer : A

Solution : Here, `r= 3.2xx10^(-15)m` <br> charge on `alpha`-particle, `q_(1)=q_(2)= 2xx1.6xx10^(-19)C` <br> Now, `F= 1/(4piepsilon_(0))*(q_(1)q_(2))/(r^(2))` <br> `=9 xx 10^(9)xx((2xx1.6xx10^(-19))^(2))/((3.2xx10^(-15))^(2))=90 N`