Bring Science Home A physics problem from Science Buddies Key concepts Physics Free fall Forces Gravity Mass Inertia Introduction Background Some 1,800 years later, in late 16th-century Italy, the young scientist and mathematician Galileo Galilei questioned Aristotle's theories of falling objects. He even performed several experiments to test Aristotle's theories. As legend has it, in 1589 Galileo stood on a balcony near the top of the Tower of Pisa and dropped two balls that were the same size but had different densities. Although there is debate about whether this actually happened, the story emphasizes the importance of using experimentation to test scientific theories, even ones that had been accepted for nearly 2,000 years. Materials • Two balls of the same size, but different mass. For example, you could use a metal and a rubber ball or a wooden and a plastic ball, as long as the two balls are about the same size. If two spherical balls like this are unavailable, you could try something like an apple and a similar-size round rock. • A ladder or step stool • A video camera and a helper (optional) Preparation • You will be dropping the two balls from the same height, at the same time. Set up the ladder or step stool where you will do your test. If you are using a heavy ball, be sure to find a testing area where the ball will not hurt the floor or ground when it lands. • If you are using a video camera to record the experiment, set up the camera now and have your helper get ready to record. • Be careful when using the step stool or ladder. Procedure • Carefully climb the ladder or step stool with the two balls. • Drop both balls at the same time, from the same height. If you are using a video camera, be sure to have your helper record the balls falling and hitting the ground. • Did one ball hit the ground before the other or did both balls hit the ground at the same time? • Repeat the experiment at least two more times. Are your results consistent? Did one ball consistently hit the ground before the other or did both balls always hit the ground at the same time? • If you videotaped your experiments, you can watch the recordings to verify your results. • Can you explain your results? • Extra: Try this experiment again but this time use balls that have the same mass but are different sizes. Does one ball hit the ground before the other or do they hit it at the same time? • Extra: Try testing two objects that have the same mass, but are different shapes. For example, you could try a large feather and a very small ball. Does one object hit the ground before the other or do they hit it at the same time? • Extra: You could try this experiment again but record it using a camera that lets you play back the recording in slow motion. If you watch the balls falling in slow motion, what do you notice about how they are falling over time? Are both objects always falling at the same speed or is one falling faster than the other at certain points in time? Observations and results Did both balls hit the ground at the same time? You should have found that both balls hit the ground at roughly the same time. According to legend, this is what Galileo showed in 1589 from his Tower of Pisa experiment but, again, it's debated whether this actually happened. If you neglect air resistance, objects falling near Earth’s surface fall with the same approximate acceleration 9.8 meters per second squared (9.8 m/s2, or g) due to Earth's gravity. So the acceleration is the same for the objects, and consequently their velocity is also increasing at a constant rate. Because the downward force on an object is equal to its mass multiplied by g, heavier objects have a greater downward force. Heavier objects, however, also have more inertia, which means they resist moving more than lighter objects do, and so heaver objects need more force to get them going at the same rate. More to explore This activity brought to you in partnership with Science Buddies Discover world-changing science. Explore our digital archive back to 1845, including articles by more than 150 Nobel Prize winners. Subscribe Now!
QUESTION #6 Asked by: Terri If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. This statement follows from the law of conservation of energy and has been demonstrated experimentally by dropping a feather and a lead ball in an airless tube. When air resistance plays a role, the shape of the object becomes important. In air, a feather and a ball do not fall at the same rate. In the case of a pen and a bowling ball air resistance is small compared to the force a gravity that pulls them to the ground. Therefore, if you drop a pen and a bowling ball you could probably not tell which of the two reached the ground first unless you dropped them from a very very high tower. Answered by: Dr. Michael Ewart, Researcher at the University of Southern California The above answer is perfectly correct, but, this is a question that confuses many people, and they are hardly satisfied by us self-assured physcists' answers. There is one good explanation which makes everybody content -- which does not belong to me, but to some famous scientist but I can't remember whom (Galileo?); and I think it would be good to have it up here. (The argument has nothing to do with air resistance, it is assumed to be absent. The answer by Dr. Michael Ewart answers that part already.) The argument goes as follows: Assume we have a 10kg ball and a 1kg ball. Let us assume the 10kg ball falls faster than the 1kg ball, since it is heavier. Now, lets tie the two balls together. What will happen then? Will the combined object fall slower, since the 1kg ball will hold back the 10kg ball? Or will the combination fall faster, since it is now an 11kg object? Since both can't happen, the only possibility is that they were falling at the same rate in the first place. Sounds extremely convincing. But, I think there is a slight fallacy in the argument. It mentions nothing about the nature of the force involved, so it looks like it should work with any kind of force! However, it is not quite true. If we lived on a world where the 'falling' was due to electrical forces, and objects had masses and permanent charges, things would be different. Things with zero charge would not fall no matter what their mass is. In fact, the falling rate would be proportional to q/m, where q is the charge and m is the mass. When you tie two objects, 1 and 2, with charges q1, q2, and m1, m2, the combined object will fall at a rate (q1+q2)/(m1+m2). Assuming q1/m1 < q2/m2, or object 2 falls faster than object one, the combined object will fall at an intermediate rate (this can be shown easily). But, there is another point. The 'weight' of an object is the force acting on it. That is just proportional to q, the charge. Since what matters for the falling rate is q/m, the weight will have no definite relation to rate of fall. In fact, you could have a zero-mass object with charge q, which will fall infinitely fast, or an infinite-mass object with charge q, which will not fall at all, but they will 'weigh' the same! So, in fact, the original argument should be reduced to the following statement, which is more accurate: If all objects which have equal weight fall at the same rate, then _all_ objects will fall at the same rate, regardless of their weight.In mathematical terms, this is equivalent to saying that if q1=q2 then m1=m2 or, q/m is the same for all objects, they will all fall at the same rate! All in all, this is pretty hollow an argument. Going back to the case of gravity.. The gravitational force is
( G is a constant, called constant of gravitation, M is the mass of the attracting body (here, earth), and m1 is the 'gravitational mass' of the object.) And newton's law of motion is
where m2 is the 'inertial mass' of the object, and a is the acceleration. Now, solving for acceleration, we find:
Which is proportional to m1/m2, i.e. the gravitational mass divided by the inertial mass. This is our old 'q/m' from the electrical case! Now, if and only if m1/m2 is a constant for all objects, (this constant can be absorbed into G, so the question can be reduced to m1=m2 for all objects) they will all fall at the same rate. If this ratio varies, then we will have no definite relation between rate of fall, and weight. So, all in all, we are back to square one. Which is just canceling the masses in the equations, thus showing that they must fall at the same rate. The equality of the two masses is a necessity for general relativity, and enters it naturally. Also, the two masses have been found to be equal to extremely good precision experimentally. The correct answer to the question 'why objects with different masses fall at the same rate?' is, 'beacuse the gravitational and inertial masses are equal for all objects.' Then, why does the argument sound so convincing? Since our daily experience and intuition dictates that things which weigh the same, fall at the same rate. Once we assume that, we have implicitly already assumed that the gravitational mass is equal to the inertial mass. (Wow, what things we do without noticing!). The rest of the argument follows easily and naturally...Answered by: Yasar Safkan, Physics Ph.D. Candidate, M.I.T. |