When an object is at height equal to radius of earth above the surface of earth what will be value of g?

Text Solution

Solution : (i) (1.) Consider the formula, `m_(g) = (GMm)/(R^(2))` <br> Take acceleration due to gravity on the surface the earth as `'g_(o)'` from equation (1). <br> (2.) Find the acceleration due to gravity `(g_(h))` at a height (h) equal to half of the radius of the Earth from equation (1). <br> Find the ratio of `g_(o) "and" g_(h)` <br> Take the value of `g_(o) "as" 9.8 m s^(-2)`. <br> Find the value of `'g_(h)'` <br> (ii) `4.36 m s^(-2)`

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