Calculate the heat released when 68.0 g of steam at 124°c is converted to water at 45°c

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released can be calculated by the following formula.

"q=ms\\Delta t"

m = Mass of sample

s = Specific heat of steam

"\\Delta t" =Temperature change

From the given,

Mass of sample = 68.0 g

Specific heat of steam = 1.99 J/(g°C)

"\\Delta t=124-100=24\u00b0C"

"q=68x1.99x24=3247 J"

s1 - Specific heat of water, 4.184 J

"\\Delta t=100-45=55\u00b0C"

"q_1=68x4.184x55=" 15648

Q=q+q1=3247+15648=18895 J

Calculate the heat released when 68.0 g of steam at 124°c is converted to water at 45°c

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