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University of Missouri - Columbia There are There are {That is because there are ways to arrange the other 4 people, ways to arrange the 2 people who refuse to be next to each other, and places to insert the problem pair in the line formed by tho other 4). Since there are ways to line up the 6 people keeping apart the 2 people who refuse to be next to each other. $\begingroup$
(a) In how many ways can 6 people be lined up to get on a bus? Answer = 4! * 3! (c) If 2 specific persons, among 6, refuse to follow each other, how many ways are possible ?Answer = 6! - 5! * 2 I can't figure out how we got the answer of part (c). May you explain how to think in order to solve such question
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How many ways can 6 people lined up to get on a bus?
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