Video Transcriptin this question, we will be solving for the empirical formula of the compound. So imperial California is the small list are the simplest form of formula of a compound. We're number one, we are given masses of The elements which is 79.8 g of carbon and 20.2 g of age. Next resolve where most of each element present here, moles of carbon is 79.8 g, divided by the molar mass of 12.1 g per mole. This is 6.64 mol. Next mode of hydrogen is 20.2g divided by 1.01 graham's sperm. All this is equals to 20 mol, solving for dividing this given most of the small as a number of multi identified. A subscript, You have 6.64 Divided by 6.64 x equals to one age is 20 Divided by 6.64. This is three therefore empirical formula Yes, C H three. Next we're number two we have given masses of and Yes, it was 225.9 g Oh is 74.1 grab. So mole of n is equal to the mass. 25.9 g divided by the molar mass of 14.1 g per mole. This is 1.85. Hole. That's real mode of Os equals two 74.1g divided by 16 grams per mole Is 4.63 mol. Next we divide this to the smallest number of malware and is 1.85 divided by 1.85 is one oh, is 4.63, divided by 1.85 in Sequels to 2.5. So we need to multiply this way to to have in in hold number. We have. This is too, And this is five, therefore in very California. HLA, here is and two oh five. Thank you. Show
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Al=20.2 g27 g/mol=0.748 molCl=79.8 g35.5 g/mol=2.25 mol Al = 20.2 g 27 g/mol = 0.748 mol Cl = 79.8 g 35.5 g/mol = 2.25 mol . We divide through both by the smaller value (i.e., 0.748) to obtain the simplest ratio, i.e., Al=0.7480.748=1Cl=2.250.748=3 Al = 0.748 0.748 = 1 Cl = 2.25 0.748 = 3 .
What is the empirical formula of a compound that is 92.3% carbon and 7.7% hydrogen?A hydrocarbon contains 92.3% by mass of carbon and 7.7% by mass of hydrogen. The empirical formula of the compound will be oose answer: CH CH5 CH CH3.
What is the empirical formula of a compound that has a carbon to hydrogen?While C2H4 is its molecular formula and represents its true molecular structure, it has an empirical formula of CH2. The simplest ratio of carbon to hydrogen in ethene is 1:2. There are two ways to view that ratio. Considering one molecule of ethene, the ratio is 1 carbon atom for every 2 atoms of hydrogen.
What is the empirical formula of a compound composed of only carbon hydrogen and oxygen?Thus, the empirical formula of the compound is C3H6O2 C 3 H 6 O 2 .
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Find the empirical formula for a compound that has 79.8% carbon, and 20.2% hydrogen.
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