Given: Concentration of sulphuric acid = 0.01 M Show To find: pH Formula: pH = `-"log"_10["H"_3"O"^+]` Calculation: Sulphuric acid (H2SO4) is a strong acid. It dissociates almost completely in the water as: \[\ce{H2SO4_{(aq)} + 2H2O_{(l)} -> 2H3O^+_{ (aq)} + SO^{2-}_{4(aq)}}\] Hence, [H3O+] = 2 × c = 2 × 0.01 M = 2 × 10-2 M From formula (i), pH = -log10[H3O+] = -log10[2 × 10-2] = `-"log"_10"2" - "log"_10"10"^-2` = `-"log"_10"2" + 2 = 2 - 0.3010` pH = 1.699 The pH of 0.01 M sulphuric acid is 1.699.  Byju's Answer Standard XII Chemistry Ostwald Dilution Law Mathematical Interpretation Calculate the... Question A 2 No worries! We‘ve got your back. Try BYJU‘S free classes today! B 2.3 No worries! We‘ve got your back. Try BYJU‘S free classes today! C 1.7 Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses D 0.3 No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Solution The correct option is C 1.7The concentration of H+ in the 0.01 M H2SO4 is =[H+]=2×0.01=2×10−2 ∴pH=−log(H+)=−log(2×10−2)=2−0.3=1.7Suggest Corrections 13 Similar questions Q. Calculate the ph of 0.05m h2so4 solution Q. Calculate the pH of 0.01 M
H2SO4. Q. Calculate the pH value of 0.01M H2SO4 solution. (log2=0.3010) Q. Calculate the pH of the resulting solution formed by mixing the following
solutions. Solve Textbooks Question Papers Install app What is the pH of a 0.010 M?A 0.010 M solution of hydrochloric acid, HCl, has a molarity of 0.010 M. This means that [H+] = 1 x 10-2 M. The pH of this aqueous solution of H+ ions is pH = 2.
What is the pH of a 0.001 M solution of H2SO4?pH = 2.69 units.
How do you find the pH of 0.1 M H2SO4?Explanation: And sulfuric acid is diprotic, and we could represent its reaction with water by the equation.... And so 0.1⋅mol⋅L−1 is 0.2⋅mol⋅L−1 with respect to H3O+ . And thus pH=−log10(0.2)=−(−0.699)=0.699 .
What is the pH of 0.00005 M H2SO4?Therefore the pH value of a 0.005 molar aqueous solution of sulphuric acid is approximately 2.0. So, the correct answer is (D).
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What is the pH of 0.010 M H2so4?
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