The required line passes through the points S(2, 1) and T(2, 3). Show Since both the given points have same x co-ordinates i.e. 2, the given points lie on a line parallel to Y-axis. ∴ The equation of the required line is x = 2. What is the equation of the line (y - 3 = m(x+2 ) Or y = m(x+2) + 3 is the line that passes through (-2, 3) and there are infinitely many such lines.
What is the equation of the line passing through the point 2 or 3?Find the equation of a line passing through the point(2, 3) and parallel to the line 2x - 3y + 8 = 0. Hence the slope of the equation is 2/3. Therefore, the equation of line is 2x - 3y + 5 = 0.
What is an equation of the line that passes through the point (Summary : The equation of the line that passes through (-2, 3) and is parallel to 2x + 3y = 6 is 2x + 3y - 5 = 0.
How do you find an equation of a line passing through the points?How to Find the Equation of a Line from Two Points. Find the slope using the slope formula. ... . Use the slope and one of the points to solve for the y-intercept (b). ... . Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.. |